Checking Pangram or Not
Given string is a Pangram or not? Pangram is a sentence or line of string containing all the alphabet in English at-least once.
Examples:
Input: The quick brown fox jumps over the lazy dog
Output: Given string is a Pangram
Input: Hello Java Discover
Output: Given string is NOT a Pangram
Input: Pack my box with five dozen liquor jugs
Output: Given string is a Pangram
Lets see simple program to check whether given string is Pangram or not with O(N) complexity.
OUTPUT:
Examples:
Input: The quick brown fox jumps over the lazy dog
Output: Given string is a Pangram
Input: Hello Java Discover
Output: Given string is NOT a Pangram
Input: Pack my box with five dozen liquor jugs
Output: Given string is a Pangram
Lets see simple program to check whether given string is Pangram or not with O(N) complexity.
- Here create an integer array of size 26 and count variable to check all 26 characters occurred at-least once.
- Iterate through the each characters of given string and convert it to upper case irrespective of alphabets.
- Next check for whether its decimal values is between 65 to 90 and if its, then mark as 1 in integer array @ respective index's and also increment the character count.
public class Pangram { public static void main(String[] args) { int val[] = new int[26]; int chCount = 0; String str = "Pack my box with five dozen liquor jugs"; for (int i =0;i<str.length();i++) { int tmp = (int)Character.toUpperCase(str.charAt(i)); if(tmp >= 65 && tmp <=90) { if(val[tmp-65] == 0) { val[tmp-65] = 1; chCount++; } } if(chCount == 26) break; } if(chCount == 26) System.out.println("Given string is a Pangram"); else System.out.println("Given string is NOT a Pangram"); } }
OUTPUT:
Given string is a Pangram