Sorting Integer array without any sorting algorithm or loop ?

In this tutorial we will see about how to sort and print the integer array without using any sorting algorithm or without using any loop to sort. Here it comes the Data Structure and we are going to use Binary Search Tree with In-order traversal. Just need to create BST with the given array and traverse through BST using In-order traversal. By this way we can sort given array without using any sorting algorithm or loop to sort the given array.

Lets see simple Java code how to create BST with the given integer array and to traverse through BST and print the given array in sorted order.

class BST {

 BST left; // Left subtree
 BST right; // Right subtree
 int data; // Element

 public BST(int data) {
  this.data = data;
 }
}


public class SortingWithoutLoop {

 public static void main(String[] args) {

  int val[] = new int[] { 5, 8, 3, 7, 0, 43, 65, 8, 2, 89, 25 };
  BST root = new BST(val[0]);
  for (int i = 1; i < val.length; i++) {
   BST lastNode = getLastNode(root, val[i]);
   if (val[i] > lastNode.data) {
    BST tmp = new BST(val[i]);
    lastNode.right = tmp;
   } else {
    BST tmp = new BST(val[i]);
    lastNode.left = tmp;
   }
  }
  
  inOrderTraversal(root);
 }

 public static BST getLastNode(BST root, int val) {

  if (root.right != null && val > root.data) {
   return getLastNode(root.right, val);
  } else if(root.left != null && val < root.data){
   return getLastNode(root.left, val);
  }
  return root;
 }

 public static void inOrderTraversal(BST root) {

  if (root.left != null) {
   inOrderTraversal(root.left);
  }

  System.out.print(root.data + ", ");

  if (root.right != null) {
   inOrderTraversal(root.right);
  }
 }
}

OUTPUT:

0, 2, 3, 5, 8, 8, 25, 43, 65, 89,